1.source port 80
2.Umass ip address: 128.119.245.12, port: 80
3. was unable to create my own
4. The tcp syn has a value of 0. what identifies it as a syn segment is the value "1 syn:set"
5. The ackknowlegement number is 1. umass website determines this value because it is acknlowleging it as the syn value.
6. The sequence number is 1.
7-8. was confused on what i where i was to find the answers
9. minimum window size 16425. it doesnt throttle the buffer because of its window size is to large and will keep growing.
10. No, because sequence numbers are increasing proportionally.
11. The reciever recieves 16425 bytes of data per packet.
12. 16424/ .82977= 19.79 kb/sec
13. The slow start begins at the beginning of the connection and ends after. In the text examples, too much data is being sent on purpose so the network becomes congested almost imediately. In this example it is being sent in small amounts so there is no congestion
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